2x^2-2x+36=180

Solution for 2x^2-2x+36=180 equation:

2x^2-2x+36=180

We move all terms to the left:

2x^2-2x+36-(180)=0

We add all the numbers together, and all the variables

2x^2-2x-144=0

a = 2; b = -2; c = -144;
Δ = b2-4ac
Δ = -22-4·2·(-144)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-34}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+34}{2*2}=\frac{36}{4}
=9
$